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13x^2-91=13
We move all terms to the left:
13x^2-91-(13)=0
We add all the numbers together, and all the variables
13x^2-104=0
a = 13; b = 0; c = -104;
Δ = b2-4ac
Δ = 02-4·13·(-104)
Δ = 5408
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5408}=\sqrt{2704*2}=\sqrt{2704}*\sqrt{2}=52\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-52\sqrt{2}}{2*13}=\frac{0-52\sqrt{2}}{26} =-\frac{52\sqrt{2}}{26} =-2\sqrt{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+52\sqrt{2}}{2*13}=\frac{0+52\sqrt{2}}{26} =\frac{52\sqrt{2}}{26} =2\sqrt{2} $
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